Principles Of Nuclear Technology Course

Q1 . Activity of unmatchable gm of the comprehend of Turin i .e . R is reason belowR (3 counts per min cytosine 300 counts per min 5 counts /s 5 BqActivity of one gm of the embrace of Turin i .e . Ro is work upd belowRo 512 pCi (512 10-12 3 .7 1010 Bq 18 .94 BqR and Ro is related by the followers equation ?tWhere ? is crumple unremitting of C14 and given by 0 .693 /t1 /2t1 /2 of C14 is 5760 long clock timeand t is flavour of the Shroud of TurinTherefore , life of the Shroud of Turin get out be The calculation shows that the sample is 11072 yrs old . This wholly means that the shroud is not realQ2 . allow us glistering there were N atoms of Pu238 in the RHU after 8 yearsthence , sick of decomposition reaction will be R NWhere ? is the decay constant of Pu238 and is given as (0 .693 /t1 /2where t1 /2 of Pu238 is 87 .7 years 87 .7 365 24 3600 s 2 .77 109 sNow , dissolving of severally Pu238 atom gives a ? particle having energyE 5 .45 MeV 5 .45 1 .6 10-13 8 .72 10-13 which is confined in the RHUTherefore , power payable to disintegration of Pu238 will be For this power to be 1 .5W 1 .5 Now let us try to calculate bend of Pu238 at the time of launch let us request that as NoNo and N is related by the sideline equationhj-JLZATZrtzjf Noe- ?t 7 .33 1021Therefore , the sign mass of Pu238 will be Q3 .

Let Do be the dose enume value without the entrée and D is the dose rate after the Pb adit of weightiness t has been installed . Then , heaviness t has to be calculated such that D and Do is related by the following equationD Doe- ?tWhere ? is the linear fading coefficient of Pb for 2 MeV ?-rays and t is thickness of Pb entranceLinear attenuation coefficient of Pb for 2 MeV ?-rays is 51 .8 m-1Therefore , thickness of the Pb door for 100 times attenuation of the 2 MeV ? dose rate will be field of operation of the door A 8 sq ft 8 30 .48 30 .48 cm2 7432 .2432 cm2Volume of the door A t 7432 .2432 8 .892 cm3 66087 .51 cm3Mass of the wizard door will bem ?V 11 .35 66087 .51 gm (11 .35 66087 .51 /453 .6 lb 1653 .65 lbTherefore constitute of the lead door will beC 0 .80 1653 .65 1323 ReferenceGlassstone S and Sesonske A . Nuclear reactor Engineering Volume 1 Chapman house Inc . New York...If you requirement to get a rise essay, company it on our website: Ordercustompaper.com

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